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Not really a range report, I just felt this topic belonged here.
We had a discussion on the drop of a bullet at extreme distances on another forum and I was wondering what the drop is and how it's measured (from what point in it's flight)?
After reading my book on accuracy and bench rest shooting this still isn't clear to me.
The question was- what's the MOA of a bullet at 2000 meters? The proposed answer is 225 FEET.
I am not arguing this assumption/fact, but would like to know if it is in reality a fact or theory?
In order to assume that it drops 225 feet then it stands to reason that the gun would be pointing to that elevation above the target on flat land. If gravity causes the bullet to form a perfect arc as it ascends and then descends, then the bullet theoretically hits the apogee at 1000 meters which would be the point of aim (of the muzzle of the gun) correct? But this can't happen outside of a perfect vacuum, so in reality the bullet can't fly in a perfect arc and would be acted upon negatively by drag in the atmosphere which would cause the bullet to slow exponentially as it moves father from the muzzle thereby creating more of an ellipse than a true arc since as the bullet slows it's descent will accelerate also. (Note- insert the correct terminology where appropriate) I realize the flight time of a bullet at that close of a distance is measured in a very few seconds (2? 3? at most) however this still seems to be enough time to be acted upon by the density of the atmosphere since it can be acted upon severely by a cross wind at much shorter distances.
So can anyone clear this up on a level that I can understand it? Lots of mathematics would only serve to confuse me more. Are there any websites that clearly explain this? I've sorta looked but haven't found a good one yet. Thanks!
We had a discussion on the drop of a bullet at extreme distances on another forum and I was wondering what the drop is and how it's measured (from what point in it's flight)?
After reading my book on accuracy and bench rest shooting this still isn't clear to me.
The question was- what's the MOA of a bullet at 2000 meters? The proposed answer is 225 FEET.
I am not arguing this assumption/fact, but would like to know if it is in reality a fact or theory?
In order to assume that it drops 225 feet then it stands to reason that the gun would be pointing to that elevation above the target on flat land. If gravity causes the bullet to form a perfect arc as it ascends and then descends, then the bullet theoretically hits the apogee at 1000 meters which would be the point of aim (of the muzzle of the gun) correct? But this can't happen outside of a perfect vacuum, so in reality the bullet can't fly in a perfect arc and would be acted upon negatively by drag in the atmosphere which would cause the bullet to slow exponentially as it moves father from the muzzle thereby creating more of an ellipse than a true arc since as the bullet slows it's descent will accelerate also. (Note- insert the correct terminology where appropriate) I realize the flight time of a bullet at that close of a distance is measured in a very few seconds (2? 3? at most) however this still seems to be enough time to be acted upon by the density of the atmosphere since it can be acted upon severely by a cross wind at much shorter distances.
So can anyone clear this up on a level that I can understand it? Lots of mathematics would only serve to confuse me more. Are there any websites that clearly explain this? I've sorta looked but haven't found a good one yet. Thanks!
question 'how far can it shoot'. 
elev.png 
Yeah, I was hoping you'd recognize your answer over there 
, So now the answer is 448 INCHES or 4.48 Inches? 
I haven't looked yet. 448"=37.33' I never did get out to see where mine aims when I aim a mile out. Prolly won't work anyway because I live on top of a hill. 